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If $x+\frac{1}{x}=4$, then the value of $x^4 +(\frac{1}{x})^4$ is : |
14 196 16 194 |
194 |
$(x - \frac{1}{x}) = a$ (x2 + x-2) = (a)2 + 2 = b = (x4 + x-4) = b2 - 2 If $x+\frac{1}{x}=4$, (x2 + x-2) = (4)2 - 2 = 14 then the value of $x^4 +(\frac{1}{x})^4$ is = (14)2 - 2 = 194 |
