Ram needs to reach the examination center in 6 hours, the journey itself is 250 km. If Ram has covered (3/5)th of the distance in 3.5 hours then what is the speed required to reach the destination 30 minutes early than the required time ?

50 km/h

Total distance = 250 km

Total time = 6 hours

\(\frac{3}{5}\) th of distance covered in 3.5 hours . i.e. 150 km

Remaining distance = 250 - 150 = 100 km

Remaining time = 6 - 3.5 = 2.5 hours

To cover distance 30 minutes earlier i.e. 2 hours

Speed = \(\frac{100}{2}\)

= 50 km/h