Ram needs to reach the examination center in 6 hours, the journey itself is 250 km. If Ram has covered (3/5)th of the distance in 3.5 hours then what is the speed required to reach the destination 30 minutes early than the required time ?
Answer & explanation
Correct answer: option 1
Total distance = 250 km
Total time = 6 hours
\(\frac{3}{5}\) th of distance covered in 3.5 hours . i.e. 150 km
Remaining distance = 250 - 150 = 100 km
Remaining time = 6 - 3.5 = 2.5 hours
To cover distance 30 minutes earlier i.e. 2 hours
Speed = \(\frac{100}{2}\)
= 50 km/h