The area of the region bounded by the curve $y = x + 1$, x-axis and the lines $x = 2$ and $x = 3$ is

$\frac{7}{2}$ sq. units

The correct answer is Option (2) → $\frac{7}{2}$ sq. units

Given: $y = x + 1$, bounded by $x$-axis, $x = 2$ and $x = 3$

Area $A = \int_2^3 (x+1) \, dx = \left[ \frac{x^2}{2} + x \right]_2^3$

Area $A = \frac{15}{2} - 4 = \frac{7}{2}$

Answer: $\frac{7}{2}$ sq. units