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Home/Practice questions/Chemistry
ChemistryPhysical: Chemical Kinetics

Select the incorrect statement with reference to Arrhenius theory.

Select the incorrect statement with reference to Arrhenius theory.

Answer & explanation+

Correct answer: option 3

The correct answer is Option (3) → The plot of rate constant (k) vs 1/T is a straight line.

According to the Arrhenius theory, reactant molecules must collide and form an unstable activated complex, which needs the activation energy Ea. The rate constant depends on temperature as:

    \( \displaystyle k=A\,e^{-E_a/RT} \)

This is an exponential relation, so k plotted against 1/T gives a curve, not a straight line. Taking natural logarithms gives a straight-line form:

    \( \displaystyle \ln k=\ln A-\frac{E_a}{R}\times\frac{1}{T} \)

    \( \displaystyle \log k=\log A-\frac{E_a}{2.303R}\times\frac{1}{T} \)

  • Option (1) Some energy is released when the complex decomposes to form products. — A correct statement of Arrhenius theory. The activated complex lies at the top of the energy barrier, so energy is released as it breaks up into products.

  • Option (2) The final enthalpy of the reaction depends upon the nature of reactants and products. — A correct statement of Arrhenius theory. The reaction enthalpy is the difference between the energies of products and reactants, whatever the path.

  • Option (3) The plot of rate constant (k) vs 1/T is a straight line. — The incorrect statement. It is the plot of ln k (or log k) vs 1/T that is a straight line, with slope −Ea/R; k itself against 1/T gives a curve.

  • Option (4) Activation Energy for the catalyzed as well as for uncatalysed reaction can be calculated by the Arrhenius equation. — A correct statement of Arrhenius theory. For either reaction, measuring k at two temperatures gives Ea: \( \log\frac{k_2}{k_1}=\frac{E_a}{2.303R}\times\frac{T_2-T_1}{T_1T_2} \)

NCERT (2026-27 edition):
Temperature Dependence of the Rate of a Reaction – …

Textbook extract

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