Practicing Success
Practicing Success
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If the line $\vec{r}=(\hat{i}-2\hat{j}+\hat{k})+\lambda (2\hat{i}+\hat{j}+2\hat{k})$ is parallel to the plane $\vec{r}. (3\hat{i}-2\hat{j}+m\hat{k})=14, $ then value of m is : |
-1 2 1 -2 |
-2 |
The correct answer is Option (4) → -2 Line parallel to plane $⇒(2\hat i+\hat j+2\hat k).(3\hat i-2\hat j+m\hat k)=0$ $6-2+2m=0$ $m=-2$ |
