If the line $\vec{r}=(\hat{i}-2\hat{j}+\hat{k})+\lambda (2\hat{i}+\hat{j}+2\hat{k})$ is parallel to the plane $\vec{r}. (3\hat{i}-2\hat{j}+m\hat{k})=14, $ then value of m is :
Answer & explanation
Correct answer: option 4
The correct answer is Option (4) → -2
Line parallel to plane
$⇒(2\hat i+\hat j+2\hat k).(3\hat i-2\hat j+m\hat k)=0$
$6-2+2m=0$
$m=-2$