If B = \(\begin{bmatrix}x&0\\0&y\end{bmatrix}\) then the value of B-B
Answer & explanation
Correct answer: option 3
Given that B = \(\begin{bmatrix}x&0\\0&y\end{bmatrix}\)
Then B-B = \(\begin{bmatrix}x&0\\0&y\end{bmatrix}\) - \(\begin{bmatrix}x&0\\0&y\end{bmatrix}\)
= \(\begin{bmatrix}x-x&0\\0&y-y\end{bmatrix}\)
= \(\begin{bmatrix}0&0\\0&0\end{bmatrix}\)