Practicing Success
Practicing Success
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Let $f(x) = 6x^{4/3} – 3x^{1/3}, x [–1, 1]$. Then |
The maximum value of f(x) on [–1, 1] is 3 The maximum value of f(x) on [–1, 1] is 9 The minimum value of f(x) on [–1, 1] is 0 None of these |
The maximum value of f(x) on [–1, 1] is 9 |
$f’(x) = 0$. Thus $f’(x) = 0$ when $x = 1/8$ and $f’(x)$ does not exist when $x = 0$. Now $f(–1) = 9, f(0) =0, f (1/8) = – 9/8$ and $f(a) = 3$. The maximum value of $f (x)$ on [–1, 1] is 9 |
