If the angular velocity of coil in an AC generator is doubled while keeping other parameters constant, the maximum induced emf
Answer & explanation
Correct answer: option 3
The correct answer is Option (3) → is doubled
Maximum induced emf in an AC generator:
$\mathcal{E}_\text{max} = NAB\omega$
Where $N$ = number of turns, $A$ = area of coil, $B$ = magnetic field, $\omega$ = angular velocity.
If angular velocity is doubled: $\omega' = 2\omega$, then:
$\mathcal{E}'_\text{max} = NAB(2\omega) = 2 \cdot NAB\omega = 2 \mathcal{E}_\text{max}$
Final Answer: Maximum induced emf will be doubled