If the angular velocity of coil in an AC generator is doubled while keeping other parameters constant, the maximum induced emf |
remains the same is halved is doubled is quadrupled |
is doubled |
The correct answer is Option (3) → is doubled Maximum induced emf in an AC generator: $\mathcal{E}_\text{max} = NAB\omega$ Where $N$ = number of turns, $A$ = area of coil, $B$ = magnetic field, $\omega$ = angular velocity. If angular velocity is doubled: $\omega' = 2\omega$, then: $\mathcal{E}'_\text{max} = NAB(2\omega) = 2 \cdot NAB\omega = 2 \mathcal{E}_\text{max}$ Final Answer: Maximum induced emf will be doubled |