The first order reaction is 20% complete in 10 minutes. What is the rate constant of the reaction?
Answer & explanation
Correct answer: option 2
For first order reaction,
k = \(\frac{2.303}{t}\)log\(\frac{a}{a-x}\)
k = \(\frac{2.303}{10}\)log\(\frac{100}{80}\)
k = \(\frac{2.303}{10}\)log\(\frac{5}{4}\)
k = \(\frac{2.303}{10}\)(log5 - log4)
k = \(\frac{2.303}{10}\)(0.69 - 0.60)
k = \(\frac{2.303}{10}\) x 0.09
k ≈ 0.0223 min-1