A number when divided by 95 leaves a remainder 43. If the same number…

The correct answer is Option (2) → 5

Let the number be N.

Given:

$N \equiv 43 \pmod{95}$

Since

$95 = 19 \times 5$

Now divide the congruence by 19:

$N \equiv 43 \pmod{19}$

Reduce 43 modulo 19:

$43 = 19 \times 2 + 5$

So,

$N \equiv 5 \pmod{19}$