In the given figure, if DE BC, AD = 2.5 cm, DB = 3.5 cm and EC = 4.2 cm, then the measure of AC is:
Answer & explanation
Correct answer: option 2
We know that ,
\(\frac{AD}{DB}\) = \(\frac{AE}{EC}\)
\(\frac{2.5}{3.5}\) = \(\frac{AE}{4.2}\)
\(\frac{5}{7}\) = \(\frac{AE}{4.2}\)
AE = \(\frac{5 × 4.2}{7}\)
= 3.0 cm
Now, AC = AE + EC
= 3 + 4.2
= 7.2 cm