Let $y=\log _x 5$, then $\frac{d y}{d x}=$
Answer & explanation
Correct answer: option 2
The correct answer is Option (2) - $\frac{-\log 5}{x(\log x)^2}$
$y=\log _x 5=\frac{\log 5}{\log x}$
$\frac{dy}{dx}=\frac{-\log 5}{(\log x)^2}×\frac{1}{x}$
Let $y=\log _x 5$, then $\frac{d y}{d x}=$
Correct answer: option 2
The correct answer is Option (2) - $\frac{-\log 5}{x(\log x)^2}$
$y=\log _x 5=\frac{\log 5}{\log x}$
$\frac{dy}{dx}=\frac{-\log 5}{(\log x)^2}×\frac{1}{x}$