Arrange the following compounds in the increasing order of their boiling points:

(A) Pentan-1-ol
(B) n-Butane
(C) Pentan-1-al
(D) Ethoxyethane

Choose the correct answer from the options given below:

(B), (D), (C), (A)

The correct answer is Option (3) → (B), (D), (C), (A)

Let’s analyze each compound:

• (B) n-Butane → non-polar, only weak van der Waals forces → lowest b.p.
• (D) Ethoxyethane (diethyl ether) → polar but no hydrogen bonding
• (C) Pentan-1-al → polar, stronger dipole–dipole interactions
• (A) Pentan-1-ol → hydrogen bonding → highest b.p.

Increasing order of boiling points:

$(B) < (D) < (C) < (A)$