Arrange the following compounds in the increasing order of their boiling points:
(A) Pentan-1-ol
(B) n-Butane
(C) Pentan-1-al
(D) Ethoxyethane
Choose the correct answer from the options given below:
Answer & explanation
Correct answer: option 3
The correct answer is Option (3) → (B), (D), (C), (A)
Let’s analyze each compound:
- (B) n-Butane → non-polar, only weak van der Waals forces → lowest b.p.
- (D) Ethoxyethane (diethyl ether) → polar but no hydrogen bonding
- (C) Pentan-1-al → polar, stronger dipole–dipole interactions
- (A) Pentan-1-ol → hydrogen bonding → highest b.p.
Increasing order of boiling points:
$(B) < (D) < (C) < (A)$