Practicing Success
Practicing Success
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$\begin{vmatrix}109&102&95\\6&13&20\\1&-6&-13\end{vmatrix}$ is equal to |
constant other than zero zero 100 -1997 |
zero |
Since elements of the rows are in A.P. with common difference 7, the given determinant is zero (Operations C1 - C3 and C2 - C3 make the elements in C1 and C2 proportional). Hence (B) is the correct answer. |
