If x4 + x2y2 + y4 = 133,
x2 + xy + y2 = 7, then
find x2 - xy + y2 .
Answer & explanation
Correct answer: option 1
Formula → x4 + y4 + x2y2 = (x2 + y2 + xy) × (x2 + y2 - xy)
⇒ 133 = 7 × (x2 + y2 - xy)
⇒ x2 + y2 - xy = \(\frac{133}{7}\) = 19
If x4 + x2y2 + y4 = 133,
x2 + xy + y2 = 7, then
find x2 - xy + y2 .
Correct answer: option 1
Formula → x4 + y4 + x2y2 = (x2 + y2 + xy) × (x2 + y2 - xy)
⇒ 133 = 7 × (x2 + y2 - xy)
⇒ x2 + y2 - xy = \(\frac{133}{7}\) = 19