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CUET
-- Mathematics - Section A
Linear Programming
If $x+y ≤3,x≥0,y≥0$ are constraints, then for $z=x-y $, Max Z is
0
6
3
Cannot be determined
The correct answer is Option (3) → 3
Objective function is optimal only at corner points of feasible region.
$Z(3,0)=3-0=3$
