Practicing Success
Practicing Success
CUET Preparation Today
Calculate the mean free time between collision in copper at room temperature. Given n = 8.5$\times$ 1028 m–3 $\rho/m$= 1.72 $\times$ 10–8 $\Omega$, e = 1.60 $\times$ 10–19 c and m = 9.11 $\times$ 10–31 kg |
$ 2.4 \times 10^{-14}S$ $ 3.4 \times 10^{-14}S$ $ 5.4 \times 10^{-14}S$ $ 1.4 \times 10^{-14}S$ |
$ 2.4 \times 10^{-14}S$ |
$ T = \frac{m}{ne^2\rho} = 2.4 \times 10^{-14}S$
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