Calculate the mean free time between collision in copper at room temperature.
Given n = 8.5$\times$ 1028 m–3 $\rho/m$= 1.72 $\times$ 10–8 $\Omega$, e = 1.60 $\times$ 10–19 c and m = 9.11 $\times$ 10–31 kg
Answer & explanation
Correct answer: option 1
$ T = \frac{m}{ne^2\rho} = 2.4 \times 10^{-14}S$