Let \(\vec{a}\) be a unit vector and \(\vec{x}\) be a vector satisfying \(\left(\vec{x}-\vec{a}\right)\cdot \left(\vec{x}+\vec{a}\right)=12\) then \(\left|\vec{x}\right|\) is
Answer & explanation
Correct answer: option 3
\(\begin{aligned}\left(\vec{x}-\vec{a}\right)\cdot \left(\vec{x}+\vec{a}\right)&=12\\|\vec{x}|^{2}-|\vec{a}|^{2}&=12\\ |\vec{x}|^{2}&=13\\ |\vec{x}|&=\sqrt{13}\end{aligned}\)