What is the area of the square (in cm2) whose vertices lie on a circle of radius 5 cm?

80 50 100 75

50

We know that, Diagonal of a square = \(\sqrt {2}\)(side) Area of a square = (side)2  We have, The radius of the circle = 5 cm  Diameter of the circle = Diagonal of the square Diameter = 10cm 10 = \(\sqrt {2}\)(side) side = 5\(\sqrt {2}\) Now, the area of the square = (5\(\sqrt {2}\))2 = 50 cm2