Consider the figure given below in which a particle of weight W resting a smooth (frictional less) inclined plain AB with the help of force F acting on the particle at angle θ with the line AB. find the force F and normal reaction. |
(Wcosθ)/sinα, [Wcos(α - θ)]/cosθ (Wsinα)/cosθ, [Wcos(α + θ)]/cosθ (Wsinα)/cosθ, [Wsin(α + θ)]/cosθ none of the above |
(Wsinα)/cosθ, [Wcos(α + θ)]/cosθ |
By : Law of Sine F/sin(180 - α) = N/sin(90 + α + θ) = W/sin(90 - θ) On solving this, we get : $F = (W \sinα)/\cosθ, N = [W \cos(α + θ)]/ \cosθ$ |