Consider the figure given below in which a particle of weight W resting a smooth (frictional less) inclined plain AB with the help of force F acting on the particle at angle θ with the line AB.
find the force F and normal reaction.
Answer & explanation
Correct answer: option 2
By : Law of Sine
F/sin(180 - α) = N/sin(90 + α + θ) = W/sin(90 - θ)
On solving this, we get : $F = (W \sinα)/\cosθ, N = [W \cos(α + θ)]/ \cosθ$