A solenoid with 100 turns per metre carries a current of 1.2 A. The magnetic intensity inside the solenoid is:
Answer & explanation
Correct answer: option 2
The correct answer is Option (2) → $120 Am^{-1}$
The magnetic intensity (H) inside a solenoid is -
$H=n.I$
where,
n = Number of turns per unit length = 100 turns/m
I (Current) = 1.2 A
$H = 100×1.2=120Am^{-1}$