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A solenoid with 100 turns per metre carries a current of 1.2 A. The magnetic intensity inside the solenoid is: |
$83 Am^{-1}$ $120 Am^{-1}$ $150 Am^{-1}$ $60 Am^{-1}$ |
$120 Am^{-1}$ |
The correct answer is Option (2) → $120 Am^{-1}$ The magnetic intensity (H) inside a solenoid is - $H=n.I$ where, n = Number of turns per unit length = 100 turns/m I (Current) = 1.2 A $H = 100×1.2=120Am^{-1}$ |
