
Answer & explanation
Correct answer: option 4
$\frac{1}{F_a} = (\frac{\mu_g}{\mu_a} -1) (\frac{1}{R_1} - \frac{1}{R_2})$
$\frac{1}{F_l} = (\frac{\mu_g}{\mu_w} -1) (\frac{1}{R_1} - \frac{1}{R_2})$
$\frac{F_l}{F_a} = \frac{\frac{\mu_g}{\mu_a} -1}{\frac{\mu_g}{\mu_w} -1}$
$\frac{F_l}{20cm} = \frac{\frac{1.1}{1} -1}{\frac{1.1}{1.33} -1} = -11.4cm $
$\text{ Since focal length is negative hence its a divergent lens}$