If \(f(x)=\frac{4x+5}{x-6}, x\neq 6\) then \(f^{-1}(x)\) is equal to |
\(\frac{5x+6}{x+4},x\neq -4\) \(\frac{5x+6}{x-4},x\neq 4\) \(\frac{6x+5}{x-4},x\neq 4\) \(\frac{6x+5}{x+4},x\neq -4\) |
\(\frac{6x+5}{x-4},x\neq 4\) |
$y=\frac{4x+5}{x-6}$ so $xy-6y=4x+5⇒x(y-4)=6y+5$ so $x=\frac{6y+5}{y-4},y≠4$ $f^{-1}(x)=\frac{6x+5}{x-4},x≠4$ |