CUET Preparation Today
If $3tan^{-1}x+cot^{-1}x=\pi $, then x equals to : |
-1 1 $\frac{1}{2}$ 0 |
1 |
The correct answer is option (2) → 1 $3\tan^{-1}x+\cot^{-1}x=\pi$ $⇒2\tan^{-1}x+\frac{\pi}{2}=\pi$ so $2\tan^{-1}x=\frac{\pi}{2}$ so $\tan^{-1}x=\frac{\pi}{4}$ $⇒x=1$ |
