Practicing Success

Target Exam

CUET

Subject

Chemistry

Chapter

Inorganic: Coordination Compounds

Question:

Calculate CFSE for [FeF6]3-?

Options:

-12 Dq

+24 Dq

Zero

None of these

Correct Answer:

Zero

Explanation:

In [FeF6]3- 

x + 6(-1) = -3

x - 6 = -3

x = -3 + 6 = 3

Fe3+: [Ar]3d5

There is splitting of d-orbital in octahedral complex. (F- is a weak ligand)

Configuration: t2g3eg2 

So, CFSE = (-4 x 3)Dq + (+6 x 2)Dq = 0