A proton is projected with a speed of $4 × 10^6 m s^{-1}$ horizontally from east to west. A uniform magnetic field of strength $1.5 × 10^{-3} T$ exists in the vertically upward direction. What is the acceleration produced? (Use charge on the proton $1.6 × 10^{-19} C$ and mass of the proton = $1.67 × 10^{-27} kg$)

$5.75 × 10^{11} ms^{-2}$

The correct answer is Option (1) → $5.75 × 10^{11} ms^{-2}$