Practicing Success
Practicing Success
CUET Preparation Today
If b cos θ = a, then cosecθ + cotθ = ______. |
$\sqrt{\frac{1}{b+a}}$ $\sqrt{\frac{b-a}{b+a}}$ $\sqrt{\frac{b+a}{b-a}}$ $\sqrt{\frac{1}{b-a}}$ |
$\sqrt{\frac{b+a}{b-a}}$ |
b cos θ = a cos θ = \(\frac{a}{b}\) B = a & H = b P2 + B2 = H2 P2 + a2 = b2 P2 = b2 - a2 P = \(\sqrt { b2 - a2 }\) cosecθ + cotθ = \(\frac{b}{\sqrt { b2 - a2 }}\) + \(\frac{a}{\sqrt { b2 - a2 }}\) = $\sqrt{\frac{b+a}{b-a}}$ |
