Let E and F are events associated with an experiment. If \(P(E) = 0.4,\ P(F) = 0.8\) and \(P(F|E) = 0.6\), then \(P(E|F)\) is
Answer & explanation
Correct answer: option 3
The correct answer is Option (3) → 0.3
By the definition of conditional probability:
\(P(E \cap F) = P(E)\,P(F|E) = 0.4 \times 0.6 = 0.24\)
\( \displaystyle P(E|F) = \frac{P(E \cap F)}{P(F)} = \frac{0.24}{0.8} = 0.3 \)