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The order and degree the differential equation of all tangent lines to the parabola $x^2=4 y$, is |
2, 1 2, 2 3, 1 4, 1 |
2, 1 |
$x^2=4y⇒\frac{dy}{dx}=\frac{x}{2}$ so equation of tangent $(y-y_0)=\frac{x}{2}(x-x_0)$ so $2(y-y_0)=x^2-x_0x$ differentiating wrt x $2y'=2x-x_0$ again differentiating wrt x so $2y''=2$ so $y''=1$ order → 2, degree → 1 |
