Given expression: \(\displaystyle\frac{(0.682)^2-(0.318)^2}{0.682-0.318}\)
Answer & explanation
Correct answer: option 3
The correct answer is Option (3) → 1
The numerator is a difference of two squares, \(a^2-b^2=(a+b)(a-b)\), so the factor \(a-b\) cancels with the denominator.
\(\displaystyle\frac{(0.682)^2-(0.318)^2}{0.682-0.318}=0.682+0.318\)
The two decimals add up to a whole: \(0.682+0.318=1\)