If $sin(θ+30°)=\frac{3}{\sqrt{12}}$, then the value of θ is equal to: |
60° 15° 45° 30° |
30° |
sin(θ + 30º) = \(\frac{3 }{√12}\) = \(\frac{3 }{√12}\) × \(\frac{√12 }{√12}\) = \(\frac{3√12 }{12}\) = \(\frac{√3 }{2}\) We know, sin 60º = \(\frac{√3 }{2}\) So , (θ + 30º) = 60º θ = 30º |