Target Exam

CUET

Subject

General Test

Chapter

Quantitative Reasoning

Topic

Trigonometry

Question:

If $sin(θ+30°)=\frac{3}{\sqrt{12}}$, then the value of θ is equal to:

Options:

60°

15°

45°

30°

Correct Answer:

30°

Explanation:

sin(θ + 30º) = \(\frac{3 }{√12}\)

= \(\frac{3 }{√12}\) × \(\frac{√12 }{√12}\)

= \(\frac{3√12 }{12}\)

= \(\frac{√3 }{2}\)

We know,

sin 60º = \(\frac{√3 }{2}\)

So , (θ + 30º)  = 60º

θ = 30º