If sin(θ+30°)=3/(√12), then the value of θ is equal to:

sin(θ + 30º) = \(\frac{3 }{√12}\)

= \(\frac{3 }{√12}\) × \(\frac{√12 }{√12}\)

= \(\frac{3√12 }{12}\)

= \(\frac{√3 }{2}\)

We know,

sin 60º = \(\frac{√3 }{2}\)

So , (θ + 30º)  = 60º

θ = 30º