The conductivity of pure water is 5.5 x 10-8 Ω-1 cm-1. What is the resistance measured for this sample of water in the conductivity cell? (Given: Cell constant = 0.2063 cm-1)
Answer & explanation
Correct answer: option 1
Conductivity = Conductance x cell constant
Κ = G x σ
5.5 x 10-8 = \(\frac{1}{R}\) X 0.2063
R = 3.75 x 106 Ω