In the circuit shown ac source gives a Voltage V = 20 cos 2000t. Neglecting source resistance, the voltmeter and Ammeter reading will be.
Answer & explanation
Correct answer: option 1
$ \omega = 2000$
$ X_L = \omega L = 2000\times 5\times 10^{-3} = 10 \Omega$
$ X_C = \frac{1}{\omega C} = \frac{1}{2000\times 50\times 10^{-6}} = 10\Omega$
$\Rightarrow X_L = X_C $
$ Z = R = (4+6)\Omega = 10\Omega $
Reading of Ammeter $\Rightarrow I = \frac{V_{rms}}{Z} = \frac{10\sqrt{2}}{10} = \sqrt{2} = 1.4A$
Reading of voltmeter =$ V_L - V_C = 0$