In the circuit shown ac source gives a Voltage V = 20 cos 2000t. Neglecting source resistance, the voltmeter and Ammeter reading will be.

0 V, 1.4 A

$ \omega = 2000$

$ X_L = \omega L = 2000\times 5\times 10^{-3} = 10 \Omega$

$ X_C = \frac{1}{\omega C} = \frac{1}{2000\times 50\times 10^{-6}} = 10\Omega$

$\Rightarrow X_L = X_C $

$ Z = R = (4+6)\Omega = 10\Omega $

Reading of Ammeter $\Rightarrow I = \frac{V_{rms}}{Z} = \frac{10\sqrt{2}}{10} = \sqrt{2} = 1.4A$

Reading of voltmeter =$ V_L - V_C = 0$