Practicing Success

Target Exam

CUET

Subject

-- Mathematics - Section B1

Chapter

Vectors

Question:

If $\vec a$ and $\vec b$ are two unit vectors inclined at an angle θ such that $|\vec a +\vec b|<1$, then

Options:

$\frac{2π}{3}<θ<\frac{4π}{3}$

$θ<\frac{π}{3}$

$θ>\frac{2π}{3}$

$θ=\frac{π}{2}$

Correct Answer:

$\frac{2π}{3}<θ<\frac{4π}{3}$

Explanation:

We have,

$|\vec a +\vec b|<1$

$⇒|\vec a +\vec b|^2<1$

$⇒|\vec a|^2 +|\vec b|^2+2(\vec a.\vec b)<1$

$⇒1+1+2\cos θ<1$

$⇒2+2\cos θ<1⇒\cos θ<-\frac{1}{2}⇒\frac{2π}{3}<θ<\frac{4π}{3}$