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Maximum value of \(z=\{min(3x_{1}-10),min(-5x_{1}+5)\}\) for \(0\leq x_{1}\leq 5\) is |
\(10\) \(0\) \(-10\) None of these |
\(-10\) |
The correct answer is Option (3) → -10 \(z=\{\text{Min}(3x_{1}-10),\text{Min}(-5x_{1}+5)\}\) \(0\leq x_{1}\leq 5\) $\text{Min}(3x_{1}-10)=3×0-10=-10$ $\text{Min}(-5x_{1}+5)=-5×5+5=-20$ $∴\text{Max}Z=\text{Max}\{-10,-20\}$ $⇒-10$ |
