Maximum value of \(z=\{min(3x_{1}-10),min(-5x_{1}+5)\}\) for \(0\leq x_{1}\leq 5\) is
Answer & explanation
Correct answer: option 3
The correct answer is Option (3) → -10
\(z=\{\text{Min}(3x_{1}-10),\text{Min}(-5x_{1}+5)\}\)
\(0\leq x_{1}\leq 5\)
$\text{Min}(3x_{1}-10)=3×0-10=-10$
$\text{Min}(-5x_{1}+5)=-5×5+5=-20$
$∴\text{Max}Z=\text{Max}\{-10,-20\}$
$⇒-10$