Let test statistic of a data be represented by : $t=\frac{(0.742-0.7)}{0.04}×3=3.15$ and it is given that $t_9(0.05)=2.267;$ then select the correct option :

\( t=3.15 > t_9(0.05)\);then null hypothesis is not accepted $t=3.15 > t_9 (0.05);$ then null hypothesis is accepted $\overline{X}=0.7, \mu = 0.742; n =9; s=0.2 $ $\overline{X}= 0.742, \mu = 0.7;$ degree of freedom = 10

\( t=3.15 > t_9(0.05)\);then null hypothesis is not accepted