CUET Preparation Today
Let test statistic of a data be represented by : $t=\frac{(0.742-0.7)}{0.04}×3=3.15$ and it is given that $t_9(0.05)=2.267;$ then select the correct option : |
\( t=3.15 > t_9(0.05)\);then null hypothesis is not accepted $t=3.15 > t_9 (0.05);$ then null hypothesis is accepted $\overline{X}=0.7, \mu = 0.742; n =9; s=0.2 $ $\overline{X}= 0.742, \mu = 0.7;$ degree of freedom = 10 |
\( t=3.15 > t_9(0.05)\);then null hypothesis is not accepted |
The correct answer is Option (1) → \( t=3.15 > t_9(0.05)\);then null hypothesis is not accepted The computed t-value is, $t=3.15$ Critical t-value, $tg(0.05)=2.267$ $t>tg(0.05)$, the test static is greater than the critical value, which means we reject the hypothesis. |
