Choose the correct basic nuclear process underlying $\beta^{-}$decay from the following: |
$n \rightarrow p+e^{+}+v$ $n \rightarrow p+e^{-}+\bar{v}$ $p \rightarrow n+e^{+}+v$ $p \rightarrow n+e^{-}+v$ |
$n \rightarrow p+e^{-}+\bar{v}$ |
The correct answer is Option (2) → $n \rightarrow p+e^{-}+\bar{v}$ In beta minus decay, a neutron in an unstable nucleus decays into a proton, releasing an electron and an antineutrino. |