If tan A =2/3, then find sinA.

tan A = \(\frac{2}{3}\)

{ we know, tanθ = \(\frac{P}{B}\) }

By using pythagoras theorem,

P² + B² = H²

2² + 3² = H²

H = √13

Now,

sinA

= \(\frac{P}{H}\)

= \(\frac{2}{ √13 }\)