The solution set of the inequation $\frac{7+5x}{4}≥\frac{x}{3}-10, x \in R$ is :
Answer & explanation
Correct answer: option 4
$\frac{7+5x}{4}\ge \frac{x}{3}-10.$
$12\left(\frac{7+5x}{4}\right)\ge 12\left(\frac{x}{3}-10\right).$
$3(7+5x)\ge4x-120.$
$21+15x\ge4x-120.$
$11x\ge-141.$
$x\ge-\frac{141}{11}.$
$\text{Solution set }=\left[-\frac{141}{11},\infty\right).$