Dimensions of $\frac{1}{\mu_0ε_0}$ where symbols have their usual meanings, are
Answer & explanation
Correct answer: option 3
$ c = \frac{1}{\sqrt{\mu_0ε_0}}\, or\, \frac{1}{\mu_0ε_0}= c^2$
$ = [M^0LT^{-1}]^2=[M^0L^2T^{-2}]$
Dimensions of $\frac{1}{\mu_0ε_0}$ where symbols have their usual meanings, are
Correct answer: option 3
$ c = \frac{1}{\sqrt{\mu_0ε_0}}\, or\, \frac{1}{\mu_0ε_0}= c^2$
$ = [M^0LT^{-1}]^2=[M^0L^2T^{-2}]$