From the given diagram, answer the following questions.

‘AC’ is 23 cm in the adjoining figure. Consider the figure and answer the questions

The area of ΔDBC if DB is a straight line

$32.5 cm^2$

Here, we have, 

ΔDBC : where base (DB) = 10 + 3 = 13 cm, height (CG) = 5cm

Area of ΔBDC

$\frac{1}{2}×B×H=\frac{1}{2}×(13×5)=\frac{65}{2}=32.5 cm^2$