If △ABC ∼ △DEF such that 2AB = DE and BC = 8 cm, then the length of EF is:
Answer & explanation
Correct answer: option 1
As the ratio of corresponding side of similar triangle is equal,
Therefore,
As, \(\Delta \)ABC is similar to \(\Delta \)DEF
⇒ \(\frac{AB}{DE}\) = \(\frac{BC}{EF}\)
⇒ As we know, 2AB = DE
⇒ \(\frac{AB}{2AB}\) = \(\frac{8}{EF}\)
⇒ EF = 8 x 2 = 16 cm.
Therefore, the value of EF is 16 cm.