Arrange the following Indian states in descending order of density of population based on 2011 census:
(A) Arunachal Pradesh
(B) Gujarat
(C) Bihar
(D) Himachal Pradesh
Choose the correct answer from the options given below:
Answer & explanation
Correct answer: option 4
The correct answer is Option (4) → (C), (B), (D), (A)
(C) Bihar — first, with 1,102 persons per sq km. It lies in the fertile Ganga plain, where farming supports very many people.
(B) Gujarat — second, with 308 persons per sq km.
(D) Himachal Pradesh — third, with 123 persons per sq km. Its hilly terrain supports fewer people.
(A) Arunachal Pradesh — last, with only 17 persons per sq km, the lowest of all the states in 2011. Steep mountains and thick forests make it very thinly populated.
NCERT (2026-27): “Density of Population … The data shown in Appendix (i) give an idea of spatial variation of population densities in the country which ranges from as low as 17 persons per sq km in Arunachal Pradesh to 11,297 persons in the National Capital Territory of Delhi. Among the northern Indian States, Bihar (1102), West Bengal (1029) and and Uttar Pradesh (828) have higher densities, while Kerala (859) and Tamil Nadu (555) have higher densities among the peninsular Indian states. States like Assam, Gujarat, Andhra Pradesh, Haryana, Jharkhand, Odisha have moderate densities. The hill states of the Himalayan region and North eastern states of India (excluding Assam) have relatively low densities while the Union Territories (excluding Andaman and Nicobar islands) have very high densities of population (Appendix–i).”
Appendix (i) India: State-wise Population Distribution, Density and Growth, 2011 |
