In an isosceles triangle ABC with AB = AC and AD is perpendicular to BC, if AD = 6 cm and the perimeter of ΔABC is 36 cm, then the area of ΔABC is:
Answer & explanation
Correct answer: option 2
We know that,
Area of right angled triangle = \(\frac{1}{2}\) × Base × Height
We have,
AB = AC and AD is perpendicular to BC
and, AD = 6 cm
perimeter of ΔABC is 36 cm
We have a triplet =
10 , 8 , 6
According to this triplet the perimeter of the triangle = 10 + 10 + 8 + 8 = 36 cm ( satisfied )
So, with the help of this triplet we can conclude that,
BD = 8 and the value of BC is = 16
So, the area of the triangle = \(\frac{1}{2}\) × 8 × 6 = 48 cm2