CUET Preparation Today
For a series LCR circuit, at the condition of resonance, the value of power factor will be: |
Zero 1.0 0.2 0.5 |
1.0 |
The correct answer is Option (2) → 1.0 for power factor, $P.f=\frac{R}{Z}=\frac{R}{\sqrt{R+(X_C-X_L)^2}}$ In resonance, $X_C=X_L⇒P.f.=1$ |
