A 25 cm long bar magnet (AB) is moved with a speed of 8m/s in a magnetic field of 0.02 Tesla as shown in figure. The emf generated is:
Answer & explanation
Correct answer: option 1
The correct answer is Option (1) → 0.04 V
Using Lorentz's force,
$E=Blv$
$=0.02×\frac{25}{100}×8$
$=0.04V$