A 25 cm long bar magnet (AB) is moved with a speed of 8m/s in a magnetic field of 0.02 Tesla as shown in figure. The emf generated is: |
0.04 V 0.08 V 0.02 V 0.05 V |
0.04 V |
The correct answer is Option (1) → 0.04 V Using Lorentz's force, $E=Blv$ $=0.02×\frac{25}{100}×8$ $=0.04V$ |