the length l . breadth b, and thickness t of a block of wood were measured with the help of a measuring scale. The results with permissible errors (in cm) are :
l = 15.12 \(\pm\) 0.01
b = 10.15 \(\pm\) 0.01
t = 5.28 \(\pm\) 0.01
The percentage error in volume up to proper significant figures is :
Answer & explanation
Correct answer: option 2
Percentage error in volume is :
\(\frac{0.01}{15.12}100 + \frac{0.01}{10.15}100 + \frac{0.01}{5.28}100 = 0.35 %\)