Light from a point source in air falls on a spherical glass surface. If μ = 1.5, and radius of curvature = 20 cm. The distance of light source from the glass surface is 100 cm, at what position will the image be formed?

100 cm

The correct answer is Option (4) → 100 cm

Refractive index, $μ=1.5$

Radius of curvature, $R=20cm$

Object Distance, $u=100cm$

$\frac{μ_2}{v}-\frac{μ_1}{u}=\frac{μ_2-μ_1}{R}$

$\frac{1.5}{v}+\frac{1}{100}=\frac{1.5-1}{20}$

$v=100cm$