Target Exam

CUET

Subject

Chemistry

Chapter

Inorganic: Coordination Compounds

Question:

Statement I: Cis isomer of \([Co(en)_2Cl_2]Cl\) shows optical activity

Statement II: Cis isomer of \([Co(en)_2Cl_2]Cl\) is a symmetrical

Options:

Both Statement I and statement II are correct and statement II is the correct explanation of statement I

Both Statement I and statement II are true but statement II is not the correct explanation for statement I

Statement I is correct but Statement II is false

Statement I is false but Statement II is correct

Correct Answer:

Statement I is correct but Statement II is false

Explanation:

The correct answer is option 3. Statement I is correct but Statement II is false.

Let us break down the explanation for each statement regarding the cis isomer of \([Co(en)_2Cl_2]Cl\):

Statement I: Cis isomer of \([Co(en)_2Cl_2]Cl\) shows optical activity

To understand why this statement is true, let's delve into the concept of optical activity:

Chirality and Optical Activity: A molecule is optically active if it can rotate the plane of polarized light. This occurs if the molecule is chiral, meaning it has a non-superimposable mirror image (enantiomers).

Cis Isomer of \([Co(en)_2Cl_2]Cl\): In the cis isomer, the two ethylenediamine (en) ligands are adjacent to each other on the octahedral cobalt complex. This arrangement does not have a plane of symmetry, leading to chirality. Consequently, the cis isomer exists as a pair of enantiomers that can rotate plane-polarized light, making it optically active.

Statement II: Cis isomer of \([Co(en)_2Cl_2]Cl\) is symmetrical

To understand why this statement is false, consider the following:

Symmetry and Chirality: A molecule is symmetrical if it can be divided into two identical halves by a plane. Symmetrical molecules are generally achiral (not optically active) because they have no enantiomers.

Cis Isomer of \([Co(en)_2Cl_2]Cl\): The cis isomer has the two en ligands adjacent to each other, creating a specific 3D arrangement without a plane of symmetry. This lack of symmetry is what makes the molecule chiral and optically active. Therefore, saying the cis isomer is symmetrical is incorrect because its structure lacks a plane of symmetry.

To summarize:

Statement I is true because the cis isomer is chiral and shows optical activity. Statement II is false because the cis isomer is not symmetrical.

Therefore, the correct option is: Statement I is correct but Statement II is false