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If $6\frac{2}{3}$% of $(P+2)=43$ and $(P-3)$ % of $40=x$, then find $x$. |
250 256 460 640 |
256 |
$6\frac{2}{3}$% of $(P+2)=43$ \(\frac{20}{3× 100 }\) × ( P + 2 ) = 43 P + 2 = 645 P = 643 Now, $(P-3)$ % of $40=x$ ( 643 - 3 ) × \(\frac{40}{100 }\) = x 640 × \(\frac{2}{5 }\) = x x = 256 The correct answer is option (2) : 256 |
